document.write( "Question 247868: Please help me solve this equation $\"log3%282x-1%29-log3%28x-4%29=2\"$ \n" ); document.write( "

Algebra.Com's Answer #180708 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
Here are the important log rules
\n" ); document.write( "log (AB)=log(A)+log(B)
\n" ); document.write( "log(A/B)=log(A)+log(B)
\n" ); document.write( "C*log(A)=log(A^C)
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\n" ); document.write( " $\"log%283%2C%282x-1%29%29-log%283%2C%28x-4%29%29=2\"$
\n" ); document.write( " $\"log%283%2C%282x-1%29%29-log%283%2C%28x-4%29%29=log%283%2C9%29\"$
\n" ); document.write( " $\"log%283%2C%282x-1%29%2F%28x-4%29%29=log%283%2C9%29\"$
\n" ); document.write( " $\"%282x-1%29%2F%28x-4%29=9\"$
\n" ); document.write( " $\"2x-1=9%28x-4%29\"$
\n" ); document.write( " $\"2x-1=9x-36\"$
\n" ); document.write( " $\"-7x=-35\"$
\n" ); document.write( " $\"x=5\"$ \n" ); document.write( "

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