document.write( "Question 247814: A train left Shawnee traveling due west at 90 miles per hour. A car left Shawnee at the same time traveling due east at 60 miles per hour. How much time will pass before the train and car are 405 miles apart? \n" ); document.write( "
Algebra.Com's Answer #180697 by richwmiller(17219)\"\" \"About 
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rate*time=distance
\n" ); document.write( "and t= time
\n" ); document.write( "At first glance it might seem we don't have enough info.
\n" ); document.write( "but we are told the distance 405 and the two speeds
\n" ); document.write( "the time is the same for both car and train
\n" ); document.write( "so \r
\n" ); document.write( "\n" ); document.write( "t*90+t*60=405
\n" ); document.write( "t*(90+60)=405
\n" ); document.write( "t(150)=405
\n" ); document.write( "t=405/150
\n" ); document.write( "t=27/10
\n" ); document.write( "t=2.7 hours or 2 hrs 42 minutes\r
\n" ); document.write( "\n" ); document.write( "Are you sure the distance is not 450?
\n" ); document.write( "IF it were 450 then we have
\n" ); document.write( "t*(90+60)=450
\n" ); document.write( "t*150=450
\n" ); document.write( "t=3 hours
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