document.write( "Question 247797: A cyclist traveled at a rate of 32 mph to visit a nearby town. The cyclist averaged 10 mph on the return trip. If the round trip took 6.3 hours, find the distance to the nearby town. \n" ); document.write( "
Algebra.Com's Answer #180684 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Let d=distance to nearby town
\n" ); document.write( "Time to nearby town=d/r=d/32\r
\n" ); document.write( "\n" ); document.write( "Time for the return trip=d/r=d/10
\n" ); document.write( "Now we are told that the above two times add up to 6.3 hrs, so:\r
\n" ); document.write( "\n" ); document.write( "d/32 + d/10=6.3 multiply each term by 160
\n" ); document.write( "5d + 16d=1008
\n" ); document.write( "21d=1008
\n" ); document.write( "d=48 mi---------------distance to nearby town\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "time to nearby town=48/32=3/2 hrs
\n" ); document.write( "time to return =48/10 hrs
\n" ); document.write( "3/2+48/10=6.3
\n" ); document.write( "1.5+4.8=6.3
\n" ); document.write( "6.3=6.3\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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