document.write( "Question 247823: Please help with the following equation:
\n" ); document.write( "Write an equation of the line containing the specified point and parallel to the indicated line (3,-4), 5x-6y=4 I think I need to plug the points 3 and -4 in for x and y and solve but I am confused how to remove them both from the same side of the equation. Thank you for any help!
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Algebra.Com's Answer #180678 by Alan3354(69443)\"\" \"About 
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Write an equation of the line containing the specified point and parallel to the indicated line (3,-4), 5x-6y=4
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\n" ); document.write( "First, find the slope, m, of the line. To do that, put it into slope-intercept form y = mx + b. That means solve for y.
\n" ); document.write( "5x-6y=4
\n" ); document.write( "y = (5/6)x + something, doesn't matter.
\n" ); document.write( "The slope is 5/6
\n" ); document.write( "All lines parallel to it have the same slope.
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\n" ); document.write( "Use y = mx + b and the point to find b:
\n" ); document.write( "-4 = (5/6)*3 + b
\n" ); document.write( "b = -13/2
\n" ); document.write( "--> y = (5/6)x - 13/2 is parallel and thru the point.
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