document.write( "Question 247835: A computer dealer had 20 computers of which 3 are defective.
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document.write( "A. If she selects a computer at random what is the probability that it is defective?
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document.write( "B. If she selects computers at random, what is the probability that one of them is defective?
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document.write( "C. If she selects 3 computers at random what is the probability that all of them are defective? \n" );
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Algebra.Com's Answer #180668 by stanbon(75887) ![]() You can put this solution on YOUR website! A computer dealer had 20 computers of which 3 are defective. \n" ); document.write( "Binomial with n=20 ; p=3/20 ; x varies \n" ); document.write( "---------------------------------------------- \n" ); document.write( "A. If she selects a computer at random what is the probability that it is defective? \n" ); document.write( "P(one selected defective) = 3/20 \n" ); document.write( "--------------------------------------- \n" ); document.write( "B. If she selects computers at random, what is the probability that one of them is defective? \n" ); document.write( "That depends on how many computers she selects. \n" ); document.write( "--------------------------------------- \n" ); document.write( "C. If she selects 3 computers at random what is the probability that all of them are defective? \n" ); document.write( "P(all of 3 are defective) \n" ); document.write( "# of ways to select 3 defective: 1 \n" ); document.write( "# of ways to select 3 without restriction: 20C3 = 1140 \n" ); document.write( "P(3 of 3 are defective) = 1/1140 \n" ); document.write( "--- \n" ); document.write( "Another way to work this is: \n" ); document.write( "(3/20)(2/19)(1/18) = 1/1140 \n" ); document.write( "==================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "==================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |