document.write( "Question 247783: Please clarify the following problem: The work surface of a desk is a rectangle that is twice as long as it is wide. If the area of the desktop is 18ft.2, find the length and width of the desk.
\n" ); document.write( "I have: 2x*x=18.2
\n" ); document.write( "2x^2=18.2
\n" ); document.write( "2x^2-18.2=0
\n" ); document.write( "2(x^2-9.1)=02(x-3.016)(x+3.016)=0
\n" ); document.write( "x=3.016
\n" ); document.write( "Check: 3.016*6.032=18.19
\n" ); document.write( "(Am I figuring this right?)
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Algebra.Com's Answer #180631 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
If the 18ft.2 means 18.2 sq feet, then it's correct.
\n" ); document.write( "2x^2 = 18.2
\n" ); document.write( "x^2 = 9.1
\n" ); document.write( "x =~ 3.0166 feet
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\n" ); document.write( "I think it's meant to be 18 sqfeet
\n" ); document.write( "\"18+ft%5E2\"
\n" ); document.write( "Then, 2x^2 = 18
\n" ); document.write( "x^2 = 9
\n" ); document.write( "x = 3
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