document.write( "Question 247744: I need to find the values for X and Y in the following problem\r
\n" ); document.write( "\n" ); document.write( "(2/X)+(3/2Y)=(11/4)
\n" ); document.write( "(5/2X)-(2/Y)=(2/3)
\n" ); document.write( "

Algebra.Com's Answer #180615 by stanbon(75887)\"\" \"About 
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I need to find the values for X and Y in the following problem
\n" ); document.write( "(2/X)+(3/2Y)=(11/4)
\n" ); document.write( "(5/2X)-(2/Y)=(2/3)
\n" ); document.write( "--------------
\n" ); document.write( "Let 1/x = a ; Let 1/y = b
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\n" ); document.write( "Rewrite the equations:
\n" ); document.write( "2a + (3/2)b = 11/4
\n" ); document.write( "(5/2)a - 2b = 2/3
\n" ); document.write( "-------------------------
\n" ); document.write( "Multiply thru 1st by 4 and 2nd by 6 to get:
\n" ); document.write( "8a + 6b = 11
\n" ); document.write( "15a - 12b = 4
\n" ); document.write( "-----------------------
\n" ); document.write( "Multiply thru 1st by 2 to get:
\n" ); document.write( "16a + 12b = 22
\n" ); document.write( "15a - 12b = 4
\n" ); document.write( "---------------------
\n" ); document.write( "Add and solve for \"a\"
\n" ); document.write( "31a = 26
\n" ); document.write( "a = 26/31
\n" ); document.write( "-------------------------------
\n" ); document.write( "Substitute into 8a+6b=11 and solve for \"b\"
\n" ); document.write( "8(26/31) + 6b = 11
\n" ); document.write( "(208/31) + 6b = 11
\n" ); document.write( "6b = 133/31
\n" ); document.write( "b = 133/186
\n" ); document.write( "-------------------
\n" ); document.write( "Convert back to x and y
\n" ); document.write( "x = 1/a = 31/26
\n" ); document.write( "y = 1/b = 186/133
\n" ); document.write( "========================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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