document.write( "Question 247744: I need to find the values for X and Y in the following problem\r
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document.write( "(2/X)+(3/2Y)=(11/4)
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document.write( "(5/2X)-(2/Y)=(2/3) \n" );
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Algebra.Com's Answer #180615 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! I need to find the values for X and Y in the following problem \n" ); document.write( "(2/X)+(3/2Y)=(11/4) \n" ); document.write( "(5/2X)-(2/Y)=(2/3) \n" ); document.write( "-------------- \n" ); document.write( "Let 1/x = a ; Let 1/y = b \n" ); document.write( "------------------ \n" ); document.write( "Rewrite the equations: \n" ); document.write( "2a + (3/2)b = 11/4 \n" ); document.write( "(5/2)a - 2b = 2/3 \n" ); document.write( "------------------------- \n" ); document.write( "Multiply thru 1st by 4 and 2nd by 6 to get: \n" ); document.write( "8a + 6b = 11 \n" ); document.write( "15a - 12b = 4 \n" ); document.write( "----------------------- \n" ); document.write( "Multiply thru 1st by 2 to get: \n" ); document.write( "16a + 12b = 22 \n" ); document.write( "15a - 12b = 4 \n" ); document.write( "--------------------- \n" ); document.write( "Add and solve for \"a\" \n" ); document.write( "31a = 26 \n" ); document.write( "a = 26/31 \n" ); document.write( "------------------------------- \n" ); document.write( "Substitute into 8a+6b=11 and solve for \"b\" \n" ); document.write( "8(26/31) + 6b = 11 \n" ); document.write( "(208/31) + 6b = 11 \n" ); document.write( "6b = 133/31 \n" ); document.write( "b = 133/186 \n" ); document.write( "------------------- \n" ); document.write( "Convert back to x and y \n" ); document.write( "x = 1/a = 31/26 \n" ); document.write( "y = 1/b = 186/133 \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |