document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29943>Question 29943</A>: <I><SPAN STYLE=\"word-break: break-all;\">  hi,\r<BR>\n" );
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document.write( "   I was wondering if you could help figure how to work a couple of radical equations. I tried them tons of different ways but I don't think I have the right answers. I also have problems with 4th and 5th roots\r<BR>\n" );
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document.write( "1) square root of 1/2 plus 3square root of 3/8. I got square 2 over/divided by 2 plus 3square root 6 over/divided by 2.<BR>\n" );
document.write( "2) 5th root of 1/8. I got 5th root of 4 over/divided by 2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18060 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18060\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1) sqrt (1/2) = [sqrt 2]/2<BR>\n" );
document.write( "   3sqrt (3/8) = (3/2)sqrt(3/2)= (3/2)[sqrt 6]/2= (3/4)sqrt 6<BR>\n" );
document.write( "Adding you get [2sqrt2 +3sqrt6]/4\r<BR>\n" );
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document.write( "2) is correct\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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