document.write( "Question 247659: How do you solve \"4%2F%28m%5E2-7%29=1\"? \n" ); document.write( "
Algebra.Com's Answer #180599 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
\"4%2F%28m%5E2-7%29=1\"
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\n" ); document.write( "Multiply both sides by \"%28m%5E2-7%29\"
\n" ); document.write( "\"4+=+m%5E2-7\"
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\n" ); document.write( "Subtract 4 from both sides
\n" ); document.write( "\"0+=+m%5E2+-+11\"
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\n" ); document.write( "\"m%5E2-11+=+0\"
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\n" ); document.write( "Factor
\n" ); document.write( "\"%0D%0A%28m+%2B+sqrt%2811%29%29%28m+-+sqrt%2811%29%29+=+0%0D%0A\"
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\n" ); document.write( "So, \"m+=+sqrt%2811%29%29\" or \"m+=+-sqrt%2811%29%29\"
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