document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=247618>Question 247618</A>: <I><SPAN STYLE=\"word-break: break-all;\"> suppose (~) is an angle in standard position whose terminal side lies in quadrant II. if sin (~) = 12/13, find values of sec (~) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #180584 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=180584\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> suppose (~) is an angle in standard position whose terminal side lies in quadrant II.<BR>\n" );
document.write( "if sin (~) = 12/13, find values of sec (~)<BR>\n" );
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document.write( "sin is y/r<BR>\n" );
document.write( "y = 12 and r = 13<BR>\n" );
document.write( "x = sqrt[13^2-12^2) = sqrt(169-144) = sqrt(25) = 5<BR>\n" );
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document.write( "But x is negative in Quadrant II so x = -5<BR>\n" );
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document.write( "sec(~) = r/x = 13/-5 = -13/5<BR>\n" );
document.write( "===================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );