document.write( "Question 247553: the length of a rectangle is four times the width. the perimeter is 200ft. find the length and width. \n" ); document.write( "
Algebra.Com's Answer #180560 by College Student(505)\"\" \"About 
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The perimeter of a rectangle is the sum of all of its sides.
\n" ); document.write( "Since a rectangle has four sides, the standard equation is:
\n" ); document.write( "\"P=2L%2B2W\"\r
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\n" ); document.write( "\n" ); document.write( "However, our problem tells us the length is 4 times the width, so let:
\n" ); document.write( "x = width
\n" ); document.write( "4x = lenght\r
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\n" ); document.write( "\n" ); document.write( "Therefore, our equation becomes: \"P=2%284x%29%2B2%28x%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"200=8x%2B2x\"
\n" ); document.write( "\"200=10x\"
\n" ); document.write( "\"x=20\"\r
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\n" ); document.write( "\n" ); document.write( "Each width measures 20 feet, each lenght measures 20 feet x 4 = 80 feet.\r
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\n" ); document.write( "\n" ); document.write( "Check: \"20%2B20%2B80%2B80=200\"
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