document.write( "Question 247459: One leg of an isosceles triangle has a length of (x2 + 9)cm. The base of the isosceles triangle has a length of (5x + 12)cm. The perimeter of the triangle is 42 cm. Find the value(s) for x and the lengths of the sides. \n" ); document.write( "
Algebra.Com's Answer #180525 by stanbon(75887)\"\" \"About 
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One leg of an isosceles triangle has a length of (x^2 + 9)cm.
\n" ); document.write( "The base of the isosceles triangle has a length of (5x + 12)cm.
\n" ); document.write( "The perimeter of the triangle is 42 cm.
\n" ); document.write( "Find the value(s) for x and the lengths of the sides.
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\n" ); document.write( "There are 2 equal legs and a base.
\n" ); document.write( "2(x^2+9) +5x+12 = 42
\n" ); document.write( "2x^2 + 5x + 18 - 42 = 0
\n" ); document.write( "2x^2 + 5x - 24 = 0
\n" ); document.write( "x = [-5 +- sqrt(25-4*2*-24)]/4
\n" ); document.write( "---
\n" ); document.write( "x = [-5 +- sqrt(217)]/4
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\n" ); document.write( "Positive solution:
\n" ); document.write( "x = [-5+sqrt(217)]/4 = 2.4327..
\n" ); document.write( "---
\n" ); document.write( "leg1 = leg2 = x^2+9 = (2.4327)^2+9 = 14.9182
\n" ); document.write( "base = 5x+12 = 24.1635
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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