document.write( "Question 247435: martha walked to the park which is 12 blocks from her home and jogged back. the entire trip took 1.5 hours. if martha jogged three times faster than she walked how fast did she walk? \n" ); document.write( "
Algebra.Com's Answer #180516 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! The whole trip took 1.5 hrs. \n" ); document.write( ". \n" ); document.write( "d=rt, so t = d/r \n" ); document.write( ". \n" ); document.write( "1.5 = 12/x + 12/3x \n" ); document.write( ". \n" ); document.write( "Multiply both sides by 3x. \n" ); document.write( ". \n" ); document.write( "3x(1.5) = (3x*12)/x + (3x*12)/3x \n" ); document.write( "4.5x = 36 + 12 \n" ); document.write( "4.5x = 48 \n" ); document.write( "x = 10.667 or 10+2/3 \n" ); document.write( ". \n" ); document.write( "So, this suggests her walking speed is 10+2/3 blocks/hr and her jogging speed is 32 blocks/hr. \n" ); document.write( ". \n" ); document.write( "Checking our work, \n" ); document.write( "12 = 10.667t \n" ); document.write( "10.667t = 12 \n" ); document.write( "t = 12/10.667 \n" ); document.write( "t = 1.125 hr walking \n" ); document.write( ". \n" ); document.write( "12 = 32t \n" ); document.write( "32t = 12 \n" ); document.write( "t = 12/32 = .375 hr jogging \n" ); document.write( ". \n" ); document.write( "1.125 + .375 = 1.5 hr total \n" ); document.write( ". \n" ); document.write( "OK \n" ); document.write( " |