document.write( "Question 247337: iam a 3 digit number less than 300 iam divisible by 2 and 5 but not 3 the sum of my digits is 7 what number am i. \n" ); document.write( "
Algebra.Com's Answer #180451 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Since the number is to be divisible by both 2 and 5 it is \r\n" ); document.write( "divisible by 10. Therefore it ends in a 0. So the sum of \r\n" ); document.write( "its digits are just the sum of the first two digits. Since \r\n" ); document.write( "it has to be less than 300, the first digit can only be \r\n" ); document.write( "1 or 2. We just need to find two digits whose sum is 7, with\r\n" ); document.write( "the first one 1 or 2. 1 and 6 have sum 7, and 160 is not \r\n" ); document.write( "divisible by 3.\r\n" ); document.write( "\r\n" ); document.write( "So one answer is 160.\r\n" ); document.write( "\r\n" ); document.write( "But also 2 and 5 have sum 7, and 250 is not divisible by 3. \r\n" ); document.write( "\r\n" ); document.write( "So the other answer is 250. \r\n" ); document.write( "\r\n" ); document.write( "They didn't need to tell us it isn't divisible by 3, because\r\n" ); document.write( "it couldn't be anyway.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |