document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=247337>Question 247337</A>: <I><SPAN STYLE=\"word-break: break-all;\"> iam a 3 digit number less than 300 iam divisible by 2 and 5 but not 3 the sum of my digits is 7 what number am i. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #180446 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=180446\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "Numbers that are divisible by 5 have a last digit of either 0 or 5.  Numbers that are divisible by 2 are even numbers.  Since any number that ends in 5 is not an even number, the number we are looking for must end in 0.  Numbers that are divisible by 3 have a sum of digits that is divisible by 3.  Since 7 is not divisible by 3, any number that qualifies by the fact that the sum of the digits is 7 also qualifies on non-divisibility by 3.  Since this is a 3-digit number less than 300, the hundreds digit must be either 1 or 2.  7 minus 1 is 6, so one possibility is 160.  7 minus 2 is 5 so the other possibility is 250.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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