document.write( "Question 247171: A student walks and jogs to college each day. She averages 5km/h walking and 9km/h jogging. The distance from home to college is 8km, she makes the trip in 1 hour. How far does the student jog? \n" ); document.write( "
Algebra.Com's Answer #180433 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! averages 5km/h walking and 9km/h jogging. \n" ); document.write( "The distance from home to college is 8km, she makes the trip in 1 hour. \n" ); document.write( " How far does the student jog? \n" ); document.write( ": \n" ); document.write( "Let x = jogging dist \n" ); document.write( "then \n" ); document.write( "(8-x) = walking dist \n" ); document.write( ": \n" ); document.write( "Write a time equation: time = dist/speed \n" ); document.write( ": \n" ); document.write( "jog time + walk time = 1 hr \n" ); document.write( " \n" ); document.write( "Multiply by 45, results: \n" ); document.write( "5x + 9(8-x) = 45 \n" ); document.write( "5x - 72 - 9x = 45 \n" ); document.write( "5x - 9x = 45 - 72 \n" ); document.write( "-4x = -27 \n" ); document.write( "x = \n" ); document.write( "x = +6.75 km jogging \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution \n" ); document.write( "8 - 6.75 = 1.25 km walking \n" ); document.write( "Walk time = 1.25/5 = .25 hr \n" ); document.write( "Jog time = 6.75/9 = .75 hr \n" ); document.write( "--------------------------- \n" ); document.write( "total time for both = 1 hr \n" ); document.write( " |