document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=247268>Question 247268</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a right isosceles triangle has perimeter 12cm find its area? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #180429 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=180429\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a right isosceles triangle has perimeter 12cm find its area?<BR>\n" );
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document.write( "The sides will be s, s and s*sqrt(2)<BR>\n" );
document.write( "2s + s*sqrt(2) = 12<BR>\n" );
document.write( "s*(2 + sqrt(2)) = 12<BR>\n" );
document.write( "s = 12/(2 + sqrt(2))<BR>\n" );
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document.write( "Area = s^2/2<BR>\n" );
document.write( "A = 144/(4 + 2 + 4sqrt(2)) = 72/(3 + 2sqrt(2))<BR>\n" );
document.write( "A =~ 12.353 sq cm<BR>\n" );
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