document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=242025>Question 242025</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the perimeter of a triangle whose vertices are X(-6, 2), Y(8, 2), and Z(3, 14).  <BR>\n" );
document.write( "a.44 units<BR>\n" );
document.write( "b.42 units<BR>\n" );
document.write( "c.40 units<BR>\n" );
document.write( "d.38 units<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #180428 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=180428\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the distance between each point and add them to get the perimeter<BR>\n" );
document.write( "from point x to y is 14<BR>\n" );
document.write( "8-(-6) <BR>\n" );
document.write( "from y to z <BR>\n" );
document.write( "5^2+12^2=c^2<BR>\n" );
document.write( "25+144=169<BR>\n" );
document.write( "sqrt(169)=13\r<BR>\n" );
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document.write( "from  x to z 12 and  9<BR>\n" );
document.write( "144+81=225 sqrt 225=15<BR>\n" );
document.write( "14<BR>\n" );
document.write( "13<BR>\n" );
document.write( "15<BR>\n" );
document.write( "13+14+15=42\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );