document.write( "Question 247114: There is a group of boys and girls standing in line at the bus stop. 15 girls get on the first bus to arrive; now there are 2 boys for each girl still at the bus stop. On the second bus, 45 boys get on; now, at the bus stop, there are 5 girls for each boy. What was the original number of girls ?\r
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document.write( "(A)40 (B) 43 (C) 29 (D) 50 (E) none of these
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Algebra.Com's Answer #180423 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! There is a group of boys and girls standing in line at the bus stop. \n" ); document.write( "Let g = no. of girls \n" ); document.write( "Let b = no. of boys \n" ); document.write( ": \n" ); document.write( " 15 girls get on the first bus to arrive; now there are 2 boys for each girl still at the bus stop. \n" ); document.write( " \n" ); document.write( "b = 2(g-15) \n" ); document.write( "b = 2g - 30 \n" ); document.write( ": \n" ); document.write( "On the second bus, 45 boys get on; now, at the bus stop, there are 5 girls for each boy. \n" ); document.write( " \n" ); document.write( "cross multiply \n" ); document.write( "5(b-45) = g - 15 \n" ); document.write( "5b - 225 = g - 15 \n" ); document.write( "5b = g - 15 + 225 \n" ); document.write( "5b = g + 210 \n" ); document.write( ": \n" ); document.write( "Replace b with (2g-30) from the 1st equation \n" ); document.write( "5(2g - 30) = g + 210 \n" ); document.write( "10g - 150 = g + 210 \n" ); document.write( "10g - g = 210 + 150 \n" ); document.write( "9g = 360 \n" ); document.write( "g = \n" ); document.write( "g = 40 girls originally at the bus stop \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "To check solution find the no. of boys \n" ); document.write( "b = 2(40) - 30 \n" ); document.write( "b = 50 boys \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |