document.write( "Question 247281: Find two consecutive odd integers such that when the lesser is added to twice the greater, the result is 12 more than the greater integer \n" ); document.write( "
Algebra.Com's Answer #180419 by richwmiller(17219)\"\" \"About 
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let n=first integers
\n" ); document.write( "and n+2 the second
\n" ); document.write( "n+(2(n+2))=12+n+2\r
\n" ); document.write( "\n" ); document.write( "n+2n+4=14+n
\n" ); document.write( "3n+4=14+n
\n" ); document.write( "subtract 4 from both sides
\n" ); document.write( "3n=n+10
\n" ); document.write( "subtract n from both sides
\n" ); document.write( "2n=10
\n" ); document.write( "n=5
\n" ); document.write( " n+2=7
\n" ); document.write( "check
\n" ); document.write( "5+2(7)=12+7
\n" ); document.write( "19=19
\n" ); document.write( "ok\r
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