document.write( "Question 247190: We have the following trinomial given to us: 3x2 + bx + 2 \r
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Algebra.Com's Answer #180401 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "3x2 + bx + 2\r\n" );
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document.write( "Since 3 and 2 are both prime, they have only two factors\r\n" );
document.write( "Therefore any factorization would have to be like this:\r\n" );
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document.write( "(3x   2)(x   1)\r\n" );
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document.write( "or like this:\r\n" );
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document.write( "(3x   1)(x   2)\r\n" );
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document.write( "And since the last term, 2, is positive,\r\n" );
document.write( "the signs must be the same, so there are\r\n" );
document.write( "four possible factorizations, each of the\r\n" );
document.write( "above with + signs, and each of the above \r\n" );
document.write( "with - signs.\r\n" );
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document.write( "(3x + 2)(x + 1) = 3x2 + 5x + 2 in which case b = 5 \r\n" );
document.write( "(3x - 2)(x - 1) = 3x2 - 5x + 2 in which case b = -5\r\n" );
document.write( "(3x + 1)(x + 2) = 3x2 + 7x + 2 in which case b = 7\r\n" );
document.write( "(3x - 1)(x - 2) = 3x2 - 7x + 2 in which case b = -7\r\n" );
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document.write( "Edwin

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