document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=247175>Question 247175</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am very lost on this equation...can someone please help explain this to me. <BR>\n" );
document.write( "(x-7+5/x-1)/(x-3+1/x-1) do the denominators of x-1 cancel out???<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #180363 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=180363\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are many problems with the way you present this problem.<BR>\n" );
document.write( "It is not an equation as you wrote it. Nothing is set equal to it. It is an expression.<BR>\n" );
document.write( "let's begin by simplifying<BR>\n" );
document.write( "x-7+5=x-2 and x-3+1=x-2<BR>\n" );
document.write( "Should I assume that (x-1) is the denominator and not just x?\r<BR>\n" );
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document.write( "(x-2)/(x-1))/((x-2)/(x-1)) equals one because not only do (x-1) cancel out but also ((x-2) and part of the denominator (x-2)<BR>\n" );
document.write( "Notice the difference<BR>\n" );
document.write( "((x-2)/(x-1))/(x-2)/(x-1)\r<BR>\n" );
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document.write( "here the numerator (x-2) and part of the denominator (x-2) cancel out leaving  1/(x-1)^2\r<BR>\n" );
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document.write( "It is hard to tell what your expression was meant to be.\r<BR>\n" );
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