document.write( "Question 246676: Please solve this problem.
\n" ); document.write( "\"Angel is twice as old as Gavin.In three years,Angel will be 13 years less than twice as old as Gavin.Find their ages now.\"
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Algebra.Com's Answer #180346 by ankor@dixie-net.com(22740)\"\" \"About 
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Angel is twice as old as Gavin.
\n" ); document.write( "a = 2g
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\n" ); document.write( "In three years,Angel will be 13 years less than twice as old as Gavin.
\n" ); document.write( "a + 3 = 2(g+3) - 13
\n" ); document.write( "a + 3 = 2g + 6 - 13
\n" ); document.write( "a = 2g - 7 - 3
\n" ); document.write( "a = 2g - 10
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\n" ); document.write( "Find their ages now.
\n" ); document.write( "replace a with 2g (from the 1st statement)
\n" ); document.write( "2g = 2g - 10
\n" ); document.write( "obviously, this is not possible, no solution
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