document.write( "Question 246676: Please solve this problem.
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document.write( "\"Angel is twice as old as Gavin.In three years,Angel will be 13 years less than twice as old as Gavin.Find their ages now.\" \n" );
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Algebra.Com's Answer #180346 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Angel is twice as old as Gavin. \n" ); document.write( "a = 2g \n" ); document.write( ": \n" ); document.write( "In three years,Angel will be 13 years less than twice as old as Gavin. \n" ); document.write( "a + 3 = 2(g+3) - 13 \n" ); document.write( "a + 3 = 2g + 6 - 13 \n" ); document.write( "a = 2g - 7 - 3 \n" ); document.write( "a = 2g - 10 \n" ); document.write( ": \n" ); document.write( "Find their ages now. \n" ); document.write( "replace a with 2g (from the 1st statement) \n" ); document.write( "2g = 2g - 10 \n" ); document.write( "obviously, this is not possible, no solution \n" ); document.write( " |