document.write( "Question 247120: A book shelf containing 20 books of which 12 are on circuit theory and 8 are on Mathematics. If three books are taken out at random, find the probability that all the three are on the same subject. \n" ); document.write( "
Algebra.Com's Answer #180328 by Theo(13342)\"\" \"About 
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20 books.\r
\n" ); document.write( "\n" ); document.write( "12 on circuit theory.\r
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\n" ); document.write( "\n" ); document.write( "8 on mathematics.\r
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\n" ); document.write( "\n" ); document.write( "you pick 3 at random.\r
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\n" ); document.write( "\n" ); document.write( "probability that all 3 are on circuit theory would be 12/20 * 11/19 * 10/18\r
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\n" ); document.write( "\n" ); document.write( "probability that all 3 are on mathematics would be 8/20 * 7/19 * 6/18\r
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\n" ); document.write( "\n" ); document.write( "probability that all 3 are either on circuit theory or on mathematics would be:\r
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\n" ); document.write( "\n" ); document.write( "(12/20 * 11/19 * 10/18) + (8/20 * 7/19 * 6/18)\r
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\n" ); document.write( "\n" ); document.write( "you can see this with smaller numbers.\r
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\n" ); document.write( "\n" ); document.write( "assume 5 books total.\r
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\n" ); document.write( "\n" ); document.write( "3 on circuit theory
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\n" ); document.write( "\n" ); document.write( "you pick 2 at random.\r
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\n" ); document.write( "\n" ); document.write( "probability all on circuit theory is 3/5 * 2/4 = 6/20\r
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\n" ); document.write( "\n" ); document.write( "probability all on math is 2/5 * 1/4 = 2/20\r
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\n" ); document.write( "\n" ); document.write( "probability either all circuit theory or all math is 6/20 + 2/20 = 8/20\r
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\n" ); document.write( "\n" ); document.write( "let abcde be the books.\r
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\n" ); document.write( "\n" ); document.write( "possible permutations of 2 are:\r
\n" ); document.write( "\n" ); document.write( "ab
\n" ); document.write( "ac
\n" ); document.write( "ad
\n" ); document.write( "ae
\n" ); document.write( "ba
\n" ); document.write( "bc
\n" ); document.write( "bd
\n" ); document.write( "be
\n" ); document.write( "ca
\n" ); document.write( "cb
\n" ); document.write( "cd
\n" ); document.write( "ce
\n" ); document.write( "da
\n" ); document.write( "db
\n" ); document.write( "dc
\n" ); document.write( "de
\n" ); document.write( "ea
\n" ); document.write( "eb
\n" ); document.write( "ec
\n" ); document.write( "ed\r
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\n" ); document.write( "\n" ); document.write( "assume abc are books on circuit theory\r
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\n" ); document.write( "\n" ); document.write( "look for all permutations of ab or ac or bc\r
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\n" ); document.write( "\n" ); document.write( "that would be ab ba ac ca bc cb\r
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\n" ); document.write( "\n" ); document.write( "that should be 6 occurrences out of 20\r
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\n" ); document.write( "\n" ); document.write( "assume de are books on math.\r
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\n" ); document.write( "\n" ); document.write( "look for all permutations of de\r
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\n" ); document.write( "\n" ); document.write( "that would be de and ed\r
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\n" ); document.write( "\n" ); document.write( "that should be 2 occurrences out of 20\r
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\n" ); document.write( "\n" ); document.write( "total possible occurrences is 8 / 20 which is the same as derived above.\r
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