document.write( "Question 247120: A book shelf containing 20 books of which 12 are on circuit theory and 8 are on Mathematics. If three books are taken out at random, find the probability that all the three are on the same subject. \n" ); document.write( "
Algebra.Com's Answer #180328 by Theo(13342) You can put this solution on YOUR website! 20 books.\r \n" ); document.write( "\n" ); document.write( "12 on circuit theory.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "8 on mathematics.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you pick 3 at random.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability that all 3 are on circuit theory would be 12/20 * 11/19 * 10/18\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability that all 3 are on mathematics would be 8/20 * 7/19 * 6/18\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability that all 3 are either on circuit theory or on mathematics would be:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(12/20 * 11/19 * 10/18) + (8/20 * 7/19 * 6/18)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can see this with smaller numbers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "assume 5 books total.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3 on circuit theory \n" ); document.write( "2 on math\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you pick 2 at random.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability all on circuit theory is 3/5 * 2/4 = 6/20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability all on math is 2/5 * 1/4 = 2/20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "probability either all circuit theory or all math is 6/20 + 2/20 = 8/20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let abcde be the books.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "possible permutations of 2 are:\r \n" ); document.write( "\n" ); document.write( "ab \n" ); document.write( "ac \n" ); document.write( "ad \n" ); document.write( "ae \n" ); document.write( "ba \n" ); document.write( "bc \n" ); document.write( "bd \n" ); document.write( "be \n" ); document.write( "ca \n" ); document.write( "cb \n" ); document.write( "cd \n" ); document.write( "ce \n" ); document.write( "da \n" ); document.write( "db \n" ); document.write( "dc \n" ); document.write( "de \n" ); document.write( "ea \n" ); document.write( "eb \n" ); document.write( "ec \n" ); document.write( "ed\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "assume abc are books on circuit theory\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "look for all permutations of ab or ac or bc\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that would be ab ba ac ca bc cb\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that should be 6 occurrences out of 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "assume de are books on math.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "look for all permutations of de\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that would be de and ed\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that should be 2 occurrences out of 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "total possible occurrences is 8 / 20 which is the same as derived above.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |