document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31331>Question 31331</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Cindy will require $11,000.00 in two years.  How much money should she invest now at 9% compounded continuously so she will have that $11,000.00?\r<BR>\n" );
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document.write( "I know the formula, but I don't know how to figure it out.<BR>\n" );
document.write( "A = Pe^rt\r<BR>\n" );
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document.write( "Thanks for your help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18031 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18031\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A=$11000; r=0.09; t=2; you need to find the Principal or \"P\"<BR>\n" );
document.write( "11000=Pe^(0.09(2))<BR>\n" );
document.write( "11000=Pe^0.18<BR>\n" );
document.write( "11000=P(1.197)<BR>\n" );
document.write( "P=11000/1.19<BR>\n" );
document.write( "P=$9187.97<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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