document.write( "Question 4081: I had 3 1/2 lb... of trial mix and I ate 1/3 of a pound two days in a row. How much trial mix did I have left?
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Algebra.Com's Answer #1803 by carl(7) $\"\"$ $\"About$

You can put this solution on YOUR website!
ok.. here we go... \r
\n" ); document.write( "\n" ); document.write( "lets work this backwards... 1/3 two days in a row... so.... 1/3 + 1/3 = 2/3 right? \r
\n" ); document.write( "\n" ); document.write( "Now we started with 3 1/2 and we ate 2/3 so.... there are a couple ways to work this but... i think we should change that 3 1/2 to an improper faction... \r
\n" ); document.write( "\n" ); document.write( "3 1/2 (change to improper faction) is 7/2 (how?? 3 x 2 = 6 + 1 = 7 over 2) got it?? \r
\n" ); document.write( "\n" ); document.write( "now 7/2 - 2/3 (we need the same denomintor with fractions) so... think 6...\r
\n" ); document.write( "\n" ); document.write( "7/2 becomes 21/6 (how?? 2 / 6 = 3 x 7 = 21) and 2/3 becomes 4/6 (how?? 3 / 6 = 2 x 2 = 4)\r
\n" ); document.write( "\n" ); document.write( "SO.... 21/6 - 4/6 = 17/6 (reduce the improper faction) (how?? 6 goes into 17 2 times (12) with 5 left over... put the 5 over 12)\r
\n" ); document.write( "\n" ); document.write( "the final answer is 2 5/6. \r
\n" ); document.write( "\n" ); document.write( "Got it?\r
\n" ); document.write( "\n" ); document.write( "Carl \n" ); document.write( "

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