document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=247028>Question 247028</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x^2+8x=9  is there any way to make this understandable. I am really confused on how to solve these problems!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #180286 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=180286\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2+8x=9 is there any way to make this understandable. I am really confused on how to solve these problems!!!<BR>\n" );
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document.write( "There's more than one way.  The quadratic equation ALWAYS works, if you know about it.<BR>\n" );
document.write( "It's quicker and easier if you can factor it, tho.<BR>\n" );
document.write( "x^2+8x=9<BR>\n" );
document.write( "x^2 + 8x - 9 = 0  (always get it equal to zero)<BR>\n" );
document.write( "(x + 9)*(x - 1) = 0<BR>\n" );
document.write( "If the product is zero, either (x+9) is zero, or (x-1) is zero.<BR>\n" );
document.write( "x = -9<BR>\n" );
document.write( "x = 1\r<BR>\n" );
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