document.write( "Question 31329: Use compound the interest formulas
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document.write( "A=P(1 +r/n) ^nt and A = Pe^rt\r
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document.write( "Suppose that you have $14,000.00 to invest. Which investment yields the greater return over 10 years: 7% compounded monthly or 6.85% compounded continuously? I know what the answer is but I don't know how to get there.\r
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document.write( "Thanks for your assistance. \n" );
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Algebra.Com's Answer #18028 by Nate(3500)![]() ![]() ![]() You can put this solution on YOUR website! Compounded monthly: \n" ); document.write( "a=P(1+r)^t \n" ); document.write( "p=initial amount \n" ); document.write( "a=increased amount \n" ); document.write( "r= rate \n" ); document.write( "t=time \n" ); document.write( "----------------------------------------------- \n" ); document.write( "a=P(1+r)^t \n" ); document.write( "a=(14000)(1.07)^10 \n" ); document.write( "about $27,540.12 \n" ); document.write( "------------------------------------------------------------------------------ \n" ); document.write( "compounded monthly: \n" ); document.write( "a=P(1+r/n)^nt \n" ); document.write( "same principles, but you have to deal with compounded as well \n" ); document.write( "----------------------------------------------- \n" ); document.write( "a=P(1+r/n)^nt \n" ); document.write( "a=(14000)(1+0.0685/12)^(120) \n" ); document.write( "about $27,718.77 \n" ); document.write( "------------------------------------------------------------------------------- \n" ); document.write( "COMPOUNDED MONTHLY GIVES YOU MORE! \n" ); document.write( " |