document.write( "Question 246873: a beaker contains 15 milliliters of 20% alcohol solution. how many milliliters of a 60% alcohol solution should be added in order to make a 30% solution? \n" ); document.write( "
Algebra.Com's Answer #180212 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .20*15+.60x=.30(15+x) \n" ); document.write( "3+.60x=4.5+.30x \n" ); document.write( ".60x-.30x=4.5-3 \n" ); document.write( ".30x=1.5 \n" ); document.write( "x=1.5/.30 \n" ); document.write( "x=5 ml. of 60% alcohol is used. \n" ); document.write( "Proof: \n" ); document.write( ".20*15+.60*5=.3(15+5) \n" ); document.write( "3+3=.3*20 \n" ); document.write( "6=6 \n" ); document.write( " \n" ); document.write( " |