document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=246893>Question 246893</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x + 4y = 5<BR>\n" );
document.write( "2x + 3y = 4 \r<BR>\n" );
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document.write( "Solve this problem using elimination.<BR>\n" );
document.write( "I wasn't sure how to do it, because you can't elimate any one of those numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #180207 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=180207\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x + 4y = 5<BR>\n" );
document.write( "2x + 3y = 4 <BR>\n" );
document.write( "Solve this problem using elimination.\r<BR>\n" );
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document.write( "If we multiply both sides of the first equation by 2 and both sides of the second equation by 3 we have:\r<BR>\n" );
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document.write( "6x + 8y = 10<BR>\n" );
document.write( "6x + 9y = 12\r<BR>\n" );
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document.write( "We did this so we would have the same coefficient on x (that is 6). So now we can subtract the second equation from the first eliminating x:\r<BR>\n" );
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document.write( "(6-6)x +(8-9)y = 10-12<BR>\n" );
document.write( "(0)x + (-1)y = -2<BR>\n" );
document.write( "-y = -2<BR>\n" );
document.write( "y = 2\r<BR>\n" );
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document.write( "Now substitute y=2 in either of the original equations and solve for x.\r<BR>\n" );
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