document.write( "Question 246753: write the first four terms of the sequence defined by the recursion formula \r
\n" ); document.write( "\n" ); document.write( "a1=2\r
\n" ); document.write( "\n" ); document.write( "an=-2an-1+2, n > 1 \n" ); document.write( "
Algebra.Com's Answer #180133 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
write the first four terms of the sequence defined by the recursion formula \r
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\n" ); document.write( "\n" ); document.write( "an=-2an-1+2, n > 1
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document.write( "Substitute 2 for n:\r\n" );
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document.write( "an=-2an-1+2\r\n" );
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document.write( "a2=-2a2-1+2\r\n" );
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document.write( "a2=-2a1+2\r\n" );
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document.write( "Now substitute 2 for a1 since that is given:\r\n" );
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document.write( "a2=-2(2)+2\r\n" );
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document.write( "a2=-4+2\r\n" );
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document.write( "a2=-2 \r\n" );
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document.write( "----------\r\n" );
document.write( "Substitute 3 for n:\r\n" );
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document.write( "an=-2an-1+2\r\n" );
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document.write( "a3=-2a3-1+2\r\n" );
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document.write( "a3=-2a2+2\r\n" );
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document.write( "Now substitute -2 for a2 since that is what\r\n" );
document.write( "we just calculated:\r\n" );
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document.write( "a3=-2(-2)+2\r\n" );
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document.write( "a3=4+2\r\n" );
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document.write( "a3=6 \r\n" );
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document.write( "----------\r\n" );
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document.write( "Substitute 4 for n:\r\n" );
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document.write( "an=-2an-1+2\r\n" );
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document.write( "a4=-2a4-1+2\r\n" );
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document.write( "a4=-2a3+2\r\n" );
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document.write( "Now substitute 6 for a3 since that is what\r\n" );
document.write( "we just calculated:\r\n" );
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document.write( "a4=-2(6)+2\r\n" );
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document.write( "a4=-12+2\r\n" );
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document.write( "a4=-10 \r\n" );
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document.write( "So the first four terms, a1, a2, a3, a4 are 2, -2, 6, and -10, respectively. \r\n" );
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document.write( "Edwin

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