document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31170>Question 31170</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello! I've been asked by my teacher to solve the following proof:\r<BR>\n" );
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document.write( "Prove: If two parallel lines are cut by a transversal, then bisectors of corresponding angles are parallel.\r<BR>\n" );
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document.write( "I have tried this problem over and over but I cant seem to picture it. Therefore I'm having problems solving it. Please help! Thank You. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18013 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18013\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> LET AB AND CD BE THE PARALLEL LINES.LET XY BE A TRANSVERSAL CUTTING AB AT P AND CD AT Q.LET EF BE THE BISECTOR OF ANGLE XPB AND GH THE BISECTOR OF ITS CORRESPONDING ANGLE XQD.<BR>\n" );
document.write( "CORRESPONDING ANGLES ARE EQUAL SO..<BR>\n" );
document.write( "ANGLE XPB=ANGLE XQD....SINCE EF AND GH ARE THEIR BISECTORS....WE HAVE ....<BR>\n" );
document.write( "ANGLE XPF = ANGLE XPB/2 = ANGLE XQD/2 = ANGLE XQH....SO.....<BR>\n" );
document.write( "WE HAVE 2 LINES EF AND GH ,A TRANSVERSAL XPQY CUTS THEM AT P AND Q RESPECTIVELY.<BR>\n" );
document.write( "AND....ANGLE XPF = ANGLE XQH...WHICH ARE CORRESPONDING ANGLES . HENCE EF IS PARALLEL TO GH.SO THE BISECTORS OF CORRESPONDING ANGLES ARE PARALLEL. </SPAN>\n" );
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