document.write( "Question 246747: Alice is twice as old as Judy, who is younger than Alex by 3 years. If the sum of their ages is 27, how old is Alice? \n" ); document.write( "

Algebra.Com's Answer #180114 by College Student(505) $\"\"$ $\"About$

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Alice is twice as old as Judy, who is younger than Alex by 3 years.
\n" ); document.write( "Let Alex = x
\n" ); document.write( "Let Judy = x-3
\n" ); document.write( "Let Alice = 2(x-3)
\n" ); document.write( "If the sum of their ages is 27, our equation becomes:
\n" ); document.write( " $\"x%2B%28x-3%29%2B%282%28x-3%29%29=27\"$
\n" ); document.write( ".
\n" ); document.write( "Now solve for x to determine Alex's age.
\n" ); document.write( "Then deduct 3 to determine Judy's age.
\n" ); document.write( "Then multiply Judy's age by 2 to determine Alice's age.
\n" ); document.write( ".
\n" ); document.write( "Remember to check your answers to ensure their ages add up to 27.
\n" ); document.write( ".
\n" ); document.write( "I'll let you take it from here. :) \n" ); document.write( "

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