document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=246603>Question 246603</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a contractor mixes concrete from bags of pre-mix for small jobs. How many bags with 8% cement should he mix with 6 bags of 16% cement to produce a mix containing 11% cement?\r<BR>\n" );
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document.write( " a. 16 bags b. 12 bags c. 10 bags  d. 21 bags </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #180038 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=180038\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=bags of .08 cement needed to make .11 cement.<BR>\n" );
document.write( "6*.16=.96<BR>\n" );
document.write( "x*.08=.08x<BR>\n" );
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document.write( ".11(6+x)=.08x+.96<BR>\n" );
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document.write( ".66+.11x=.08x+.96<BR>\n" );
document.write( ".03x=.3<BR>\n" );
document.write( "x=10 bags<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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