document.write( "Question 246639: \"log+base3%282x-1%29=2\" \n" ); document.write( "
Algebra.Com's Answer #180030 by edjones(8007)\"\" \"About 
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log[3](2x-1)=2
\n" ); document.write( "3^log[3](2x-1)=3^2
\n" ); document.write( "2x-1=9
\n" ); document.write( "2x=10
\n" ); document.write( "x=5
\n" ); document.write( ".
\n" ); document.write( "Ed
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