document.write( "Question 246585: \"log5%284x%2B1%29=+log5%282x%2B7%29\" \n" ); document.write( "
Algebra.Com's Answer #180010 by dabanfield(803)\"\" \"About 
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\"log5%284x%2B1%29=+log5%282x%2B7%29\"\r
\n" ); document.write( "\n" ); document.write( "I assume this is:\r
\n" ); document.write( "\n" ); document.write( "log base5 (4x+1) - log base5 (2x+7)?\r
\n" ); document.write( "\n" ); document.write( "Then 4x+1 = 2x+7.\r
\n" ); document.write( "\n" ); document.write( "Solve for x.
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