document.write( "Question 4010: The width of a rectangle is 1 meter more than half the length of the rectangle. If the perimeter of the rectangle is 110 meters, find the width and the length. \n" ); document.write( "
Algebra.Com's Answer #1800 by gsmani_iyer(201)\"\" \"About 
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\n" ); document.write( " the formula for perimeter of rectangle = 2(l+w)
\n" ); document.write( " here let the length of the rectangle = x meters
\n" ); document.write( " So the width of the rectangle = \"x%2F2\"+1 (Given)
\n" ); document.write( " by applying the formula to get the perimeter
\n" ); document.write( " = 2 * (x + (\"x%2F2%2B1\")) = 110 meters
\n" ); document.write( " = 2 * (x + \"x%2F2\" + 1) = 110 meters
\n" ); document.write( " = 2x + x + 2
\n" ); document.write( " = 3x + 2 = 110 meters
\n" ); document.write( " = 3x = 110 - 2 = 108 meters.
\n" ); document.write( " = x = \"108%2F3\" = 36 meters
\n" ); document.write( " So the length = 36 meters
\n" ); document.write( " and the width = 19 meters (half of length + 1)
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\n" ); document.write( " I hope it is clear to you
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\n" ); document.write( "\n" ); document.write( " gsm
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