document.write( "Question 246298: From a group of boys and girls, 15 girls leave. There are then left two boys for each girl. After 45 boys leave, there are then 5 girls for each boy. The number of girls in the beginning was:\r
\n" ); document.write( "\n" ); document.write( "(A)40 (B) 43 (C) 29 (D) 50 (E) 60
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Algebra.Com's Answer #179979 by ankor@dixie-net.com(22740)\"\" \"About 
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From a group of boys and girls,
\n" ); document.write( "b = no. of boys
\n" ); document.write( "g = no. of girls
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\n" ); document.write( "then 15 girls leave. There are then left two boys for each girl.
\n" ); document.write( "\"b%2F%28g-15%29\" = \"2%2F1\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "b = 2(g-15)
\n" ); document.write( "b = 2g - 30
\n" ); document.write( ":
\n" ); document.write( "After 45 boys leave, there are then 5 girls for each boy.
\n" ); document.write( "\"%28b-45%29%2F%28g-15%29\" = \"1%2F5\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "g-15 = 5(b-45)
\n" ); document.write( "g - 15 = 5b - 225
\n" ); document.write( "g = 5b - 225 + 15
\n" ); document.write( "g = 5b - 210
\n" ); document.write( ":
\n" ); document.write( "The number of girls in the beginning was:
\n" ); document.write( "Replace b in the above equation with (2g-30) from the 1st equation:
\n" ); document.write( "g = 5(2g-30) - 210
\n" ); document.write( "g = 10g - 150 - 210
\n" ); document.write( "g = 10g - 360
\n" ); document.write( "g - 10g = -360
\n" ); document.write( "-9g = -360
\n" ); document.write( "g = \"%28-360%29%2F%28-9%29\"
\n" ); document.write( "g = +40 girls originally
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