document.write( "Question 246298: From a group of boys and girls, 15 girls leave. There are then left two boys for each girl. After 45 boys leave, there are then 5 girls for each boy. The number of girls in the beginning was:\r
\n" );
document.write( "\n" );
document.write( "(A)40 (B) 43 (C) 29 (D) 50 (E) 60
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #179979 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! From a group of boys and girls, \n" ); document.write( "b = no. of boys \n" ); document.write( "g = no. of girls \n" ); document.write( ": \n" ); document.write( "then 15 girls leave. There are then left two boys for each girl. \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "b = 2(g-15) \n" ); document.write( "b = 2g - 30 \n" ); document.write( ": \n" ); document.write( "After 45 boys leave, there are then 5 girls for each boy. \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "g-15 = 5(b-45) \n" ); document.write( "g - 15 = 5b - 225 \n" ); document.write( "g = 5b - 225 + 15 \n" ); document.write( "g = 5b - 210 \n" ); document.write( ": \n" ); document.write( "The number of girls in the beginning was: \n" ); document.write( "Replace b in the above equation with (2g-30) from the 1st equation: \n" ); document.write( "g = 5(2g-30) - 210 \n" ); document.write( "g = 10g - 150 - 210 \n" ); document.write( "g = 10g - 360 \n" ); document.write( "g - 10g = -360 \n" ); document.write( "-9g = -360 \n" ); document.write( "g = \n" ); document.write( "g = +40 girls originally \n" ); document.write( " \n" ); document.write( " |