document.write( "Question 246443: THE HYPOTENUSE OF A RIGHT TRIANGLE IS 1 INCH LONGER THAN ONE LEG AND 8 INCHES LONGER THAN THE OTHER. FIND THE LENGTH OF EACH SIDE OF THE TRIANGLE. \n" ); document.write( "
Algebra.Com's Answer #179966 by richwmiller(17219)\"\" \"About 
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right triangle
\n" ); document.write( "c^2=a^2+b^2
\n" ); document.write( "where c is the hypotenuse and a and b are the legs.\r
\n" ); document.write( "\n" ); document.write( "c=a+1
\n" ); document.write( "solve for a
\n" ); document.write( "a=c-1
\n" ); document.write( "c=b+8
\n" ); document.write( "solve for b
\n" ); document.write( "b=c-8
\n" ); document.write( "substitute
\n" ); document.write( "c^2=(c-1)^2+(c-8)^2
\n" ); document.write( "(c-1)^2=c^2-2c+1
\n" ); document.write( "(c-8)^2=c^2-16+64
\n" ); document.write( "c^2=2c^2-18c+65
\n" ); document.write( "subtract c^2
\n" ); document.write( "c^2-18c+65=0
\n" ); document.write( "13 and 5
\n" ); document.write( "13,12, 5
\n" ); document.write( "5,4,-3
\n" ); document.write( "but -3 can't be a side of a triangle
\n" ); document.write( "so we have 13, 12, and 5
\n" ); document.write( "13 is hypotenuse
\n" ); document.write( "12 and 5 are the legs\r
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-18x%2B65+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-18%29%5E2-4%2A1%2A65=64\".
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\n" ); document.write( " Discriminant d=64 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--18%2B-sqrt%28+64+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-18%29%2Bsqrt%28+64+%29%29%2F2%5C1+=+13\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-18%29-sqrt%28+64+%29%29%2F2%5C1+=+5\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-18x%2B65\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-18x%2B65+=+1%28x-13%29%2A%28x-5%29\"
\n" ); document.write( " Again, the answer is: 13, 5.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-18%2Ax%2B65+%29\"

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