document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=246382>Question 246382</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find all solutions of the equation in the interval [0,2&#960;) algebraically. Sec^2 x - sec x =2\r<BR>\n" );
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document.write( "what are the steps to do this problem? how do i start?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179964 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179964\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find all solutions of the equation in the interval [0,2&#960;) algebraically. <BR>\n" );
document.write( "Sec^2 x - sec x =2 <BR>\n" );
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document.write( "It's a quadratic in sec(x).<BR>\n" );
document.write( "sec^2 - sec - 2 = 0<BR>\n" );
document.write( "(sec - 2)*(sec + 1) = 0<BR>\n" );
document.write( "sec(x) = 2<BR>\n" );
document.write( "sec(x) = -1<BR>\n" );
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document.write( "sec(x) = 2<BR>\n" );
document.write( "x = 60º, 120º = pi/3, 2pi/3<BR>\n" );
document.write( "--------------------<BR>\n" );
document.write( "sec(x) = -1<BR>\n" );
document.write( "x = 180º = pi radians<BR>\n" );
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