document.write( "Question 246354: Please solve this equation!\r
\n" ); document.write( "\n" ); document.write( "(3)^-2\r
\n" ); document.write( "\n" ); document.write( "I have tried 1/3x3 = 1/9 but that is incorrect.\r
\n" ); document.write( "\n" ); document.write( "Thanks\r
\n" ); document.write( "\n" ); document.write( "Norman
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Algebra.Com's Answer #179942 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
The answer is correct.
\n" ); document.write( "Who told you it wasn't?\r
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\n" ); document.write( "\n" ); document.write( "(3)^-2
\n" ); document.write( "The negative means inverse
\n" ); document.write( "(3)^-2=1/(3^2)=1/9
\n" ); document.write( "You might have written 1/3x3 as 1/(3*3) to clarify that the denominator is 3*3 or 3^2\r
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