document.write( "Question 246277: 3a-2b=14
\n" ); document.write( "4a+3b=3\r
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Algebra.Com's Answer #179917 by checkley77(12844)\"\" \"About 
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3a-2b=14 MULTIPLY BY 3
\n" ); document.write( "4a+3b=3 MULTIPLY BY 2 & ADD
\n" ); document.write( "9a-6b=42
\n" ); document.write( "8a+6b=6
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\n" ); document.write( "17a=48
\n" ); document.write( "a=48/17 ans.
\n" ); document.write( "3(48/17)-2b=14
\n" ); document.write( "144/17-2b=14
\n" ); document.write( "-2b=14-144/17
\n" ); document.write( "-2b=(14*17-144)/17
\n" ); document.write( "-2b=(238-144)/17
\n" ); document.write( "-2b=94/17
\n" ); document.write( "b=(94/17)/-2
\n" ); document.write( "b=94/-34
\n" ); document.write( "b=-47/17
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