document.write( "Question 246297: Jack and Jim start at the same time to ride from place A to place B, 60 miles away. Jack travels 4miles an hour slower than Jim. Jim reaches B and at once turns back meeting Jack 12 miles from B. The rate of Jack was:\r
\n" ); document.write( "\n" ); document.write( "(A)4 mph (B) 8 mph (C) 12 mph (D) 16 mph (E) 20 mph
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Algebra.Com's Answer #179910 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
D=RT
\n" ); document.write( "72=RT OR T=72/R JIM'S EQUATION.
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\n" ); document.write( "60-12=(R-4)T
\n" ); document.write( "48=(R-4)T
\n" ); document.write( "T=48/(R-4)
\n" ); document.write( "72/R=48(R-4)
\n" ); document.write( "48R=72(R-4)
\n" ); document.write( "48R=72R-288
\n" ); document.write( "48R-72R=488
\n" ); document.write( "24R=288
\n" ); document.write( "R=288/24
\n" ); document.write( "R=12 MPH. WAS JIM'S RATE.
\n" ); document.write( "12-4=8 MPH. WAS JACK'S RATE. ANSWER. B)
\n" ); document.write( "PROOF:
\n" ); document.write( "72/12=48/8
\n" ); document.write( "6=6\r
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