document.write( "Question 246297: Jack and Jim start at the same time to ride from place A to place B, 60 miles away. Jack travels 4miles an hour slower than Jim. Jim reaches B and at once turns back meeting Jack 12 miles from B. The rate of Jack was:\r
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document.write( "(A)4 mph (B) 8 mph (C) 12 mph (D) 16 mph (E) 20 mph
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Algebra.Com's Answer #179910 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "72=RT OR T=72/R JIM'S EQUATION. \n" ); document.write( "------------------ \n" ); document.write( "60-12=(R-4)T \n" ); document.write( "48=(R-4)T \n" ); document.write( "T=48/(R-4) \n" ); document.write( "72/R=48(R-4) \n" ); document.write( "48R=72(R-4) \n" ); document.write( "48R=72R-288 \n" ); document.write( "48R-72R=488 \n" ); document.write( "24R=288 \n" ); document.write( "R=288/24 \n" ); document.write( "R=12 MPH. WAS JIM'S RATE. \n" ); document.write( "12-4=8 MPH. WAS JACK'S RATE. ANSWER. B) \n" ); document.write( "PROOF: \n" ); document.write( "72/12=48/8 \n" ); document.write( "6=6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |