document.write( "Question 246269: lucy makes a rectangle with the perimeter of 30. The lenght is twice the width. how do you work out the area? \n" ); document.write( "
Algebra.Com's Answer #179888 by ptaylor(2198)\"\" \"About 
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OK. The area of a rectangle is length multiplied width or: A=LW
\n" ); document.write( "The perimeter of a rectangle is twice the length plus twice the width or P=2L+2W\r
\n" ); document.write( "\n" ); document.write( "Now in this problem, let W=the width of the rectangle
\n" ); document.write( "Then the length, L=2W
\n" ); document.write( "So the perimeter would be:P=30= 2(2W)+2W (since L=2W)
\n" ); document.write( "So, our equation to solve to get the length and width is:
\n" ); document.write( "30=2(2W)+2W get rid of parens
\n" ); document.write( "30=4W+2W collect like terms
\n" ); document.write( "30=6W divide each side by 6
\n" ); document.write( "W=5 units
\n" ); document.write( "Then L=2W=2*5=10 units
\n" ); document.write( "Now we can look at the area:
\n" ); document.write( "A=L*W=5*10=50 square units\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "30=2*10+2*5
\n" ); document.write( "30=20+10
\n" ); document.write( "30=30
\n" ); document.write( "Hope this helps----ptaylor\r
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