document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=246250>Question 246250</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bacteria culture initially contains 2000 bacteria and doubles every half hour. The formula for the population is p(t)=2000e^kt  for some constant(k) . (You will need to find (k) to answer the following.) \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Find the size of the baterial population after 80 minutes? \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Find the size of the baterial population after 6 hours?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179877 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179877\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A bacteria culture initially contains 2000 bacteria and doubles every half hour. The formula for the population is p(t)=2000e^kt for some constant(k) . (You will need to find (k) to answer the following.)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Consider t (time) in units of minutes.<BR>\n" );
document.write( "p(t)=2000e^kt<BR>\n" );
document.write( "4000=2000e^(30k)<BR>\n" );
document.write( "2 = e^(30k)<BR>\n" );
document.write( "ln(2) = 30k<BR>\n" );
document.write( "ln(2)/30 = k<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Find the size of the baterial population after 80 minutes?<BR>\n" );
document.write( "p(80)=2000e^(80ln(2)/30)<BR>\n" );
document.write( "p(80)=12699\r<BR>\n" );
document.write( "\n" );
document.write( "Find the size of the baterial population after 6 hours?<BR>\n" );
document.write( "6 hours = 6*60 = 360 minutes<BR>\n" );
document.write( "p(360)=2000e^(360ln(2)/30)<BR>\n" );
document.write( "p(360)=8192000<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );