document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=246155>Question 246155</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My problem is to solve 2- (a-4/a+4)=(a^2-8/a+4)I think I need to multiply each side of the equation by a+4 to eliminate fractions. So I end up with (a+4)*2-(a-4)=a^2-8. That's as far as I've gotten. I would really appreciate any help to complete the problem. Thank you.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179875 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179875\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  2- (a-4/a+4)=(a^2-8/a+4)<BR>\n" );
document.write( "2(a+4)-(a-4)=a^2-8 multiply each side by a+4<BR>\n" );
document.write( "2a+8-a+4=a^2-8<BR>\n" );
document.write( "a+12=a^2-8<BR>\n" );
document.write( "a^2-a-20=0 Subtract the left side from the right.<BR>\n" );
document.write( "(a-5)(a+4)=0<BR>\n" );
document.write( "a=5 (a cannot equal -4 because there would be division by zero which is not allowed).<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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