document.write( "Question 246219: Write an equation in slope-intercept form for the line that passes through the point (-4,6) and is perpendicular to y=8x-7. \n" ); document.write( "
Algebra.Com's Answer #179856 by dabanfield(803)\"\" \"About 
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Write an equation in slope-intercept form for the line that passes through the point (-4,6) and is perpendicular to y=8x-7.\r
\n" ); document.write( "\n" ); document.write( "The slope intercept form of a line is y = mx+b where m is the slope of the line and b is the value of y when the line crosses the y-axis (or when x = 0).\r
\n" ); document.write( "\n" ); document.write( "The line y = 8x-7 is in slope-intercept form so its slope is 8. The line perpendicular to this line has a slope that is the negative reciprical of 8 which is -1/8.\r
\n" ); document.write( "\n" ); document.write( "So the new line has the equation y = -1/8x + b\r
\n" ); document.write( "\n" ); document.write( "Since the new line passes through (-4,6) we can substitute x=-4 and y=6 in the equation above so:\r
\n" ); document.write( "\n" ); document.write( "6 = (-1/8)*-4 + b
\n" ); document.write( "6 = 1/2 + b
\n" ); document.write( "b = 5.5
\n" ); document.write( "The equation of the perpendicular line has the equation y = -1/8x + 5.5\r
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