document.write( "Question 246217: What is the answer to this problem? I'm having a hard time with it?
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document.write( "A scalene triangle has three unequal sides. The perimeter of a scalene triangle is 144 m. If the first side is twice as long as the second side and the third
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document.write( "side is 24 m longer than the second side, then what are the measures of the sides?\r
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Algebra.Com's Answer #179852 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Let the first side be A, the second side B, and the third side C. \n" ); document.write( "1) A+B+C = 144 \"The perimeter of a scalene triangle is 144 m\". \n" ); document.write( "2) A = 2B \"...the first side (A) is twice as long as the second side (B)...\" \n" ); document.write( "3) C = B+24 \"...the third side (C) is 24 m longer than the second side,...\" \n" ); document.write( "In equation 1) replace the A with equation 2) and the C with equation 3). \n" ); document.write( "1a) (2B)+B+(B+24) = 144 Simplify. \n" ); document.write( "1c) 4B+24 = 144 Subtract 24 from both sides. \n" ); document.write( "1d) 4B = 120 Divide both sides by 4. \n" ); document.write( "1e)B = 30 \n" ); document.write( "2a) A = 2B = 2(30) = 60 \n" ); document.write( "3a) C = B+24 = 30+24 = 54 \n" ); document.write( "The measures of the sides are: \n" ); document.write( "A = 60 m. \n" ); document.write( "B = 30 m. \n" ); document.write( "C = 54 m. \n" ); document.write( "Check: \n" ); document.write( "A+B+C = 60+30+54 = 144 m (The given perimeter of the scalene triangle). \n" ); document.write( " |