document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=246151>Question 246151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if y varies directly as x and inversely as z^2, and y=3 when x=2 and z=4 what is the value of x when y=9 and z=4? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179848 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179848\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if y varies directly as x and inversely as z^2, and y=3 when x=2 and z=4 what is the value of x when y=9 and z=4?\r<BR>\n" );
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document.write( "Restated the above says y = k*(x/(z^2)) where k is a constant of proportionality yet to be determined.\r<BR>\n" );
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document.write( "As stated above y=3 when x=2 and z=4 so substituting in our formula:\r<BR>\n" );
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document.write( "3 = k*(2/(4^2))<BR>\n" );
document.write( "3 = k*(2/16)= k/8<BR>\n" );
document.write( "k=24\r<BR>\n" );
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document.write( "So our equation becomes y=24*(x/(z^2))\r<BR>\n" );
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document.write( "To solve the problem we need to substitute y = 9 and z = 4 and then solve for x in the equation above. \r<BR>\n" );
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document.write( " </SPAN>\n" );
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