document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=246187>Question 246187</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this word problem.\r<BR>\n" );
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document.write( "The perimeter of a rectangle is 210ft. The length is 15ft. less than twice the width. What is the length and the width? \r<BR>\n" );
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document.write( "I have tried dividing 210 by 6, getting 35 for each width, and 70 for each length. Then I added the widths (35+35), to get 70. I subtracted 15 from 70 and got a sum of 55 and divided that by  2 getting(27.5).  I then added 15 to both of my lengths (15+70+70), and divided that by 2 getting 77.5. Am I correct that the length is 77.5ft., and the width is 27.5ft.?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179831 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = 2L + 2W,  where L = length and W = width.<BR>\n" );
document.write( "We are told<BR>\n" );
document.write( "L is 15 less than 2W, so we can interpret this as<BR>\n" );
document.write( "L + 15 = 2W  ...(the length + 15 = 2W)...or equivalently,<BR>\n" );
document.write( "L = 2W -15<BR>\n" );
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document.write( "We are told P = 210.<BR>\n" );
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document.write( "Substituting we have:<BR>\n" );
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document.write( "210 = 2L + 2W<BR>\n" );
document.write( "210 = 2(2W-15) + 2W<BR>\n" );
document.write( "210 = 4W - 30 + 2W<BR>\n" );
document.write( "210 = 6W - 30<BR>\n" );
document.write( "240 = 6W<BR>\n" );
document.write( "6W = 240<BR>\n" );
document.write( "W = 40<BR>\n" );
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document.write( "L = 2W - 15 = 80 - 15 = 65<BR>\n" );
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document.write( "So the dimensions are:<BR>\n" );
document.write( "L = 65<BR>\n" );
document.write( "W = 40<BR>\n" );
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document.write( "By the way we solved it, we know L is 15 less than 2 times width.<BR>\n" );
document.write( "But we can check the perimeter.<BR>\n" );
document.write( "2L = 2(65) = 130<BR>\n" );
document.write( "2W = 2(40) = 80<BR>\n" );
document.write( "2L + 2W = 210<BR>\n" );
document.write( "Checks. </SPAN>\n" );
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